Skip to main content

Python function that generates a URL to a given S3 resource.

Project description

Python function that generates a URL to a given S3 resource.

Example

url_for_s3('static', bucket_name='my-cool-foobar-bucket',
           scheme='https', filename='pics/logo.png')

Will return: https://my-cool-foobar-bucket.s3.amazonaws.com/static/pics/logo.png

Note: this function assumes that the given resource exists on S3 and is publicly accessible.

Based loosely on Flask-S3’s url_for().

For a complete, working Flask app that demonstrates url-for-s3 in action, have a look at flask-s3-save-example.

Project details


Download files

Download the file for your platform. If you're not sure which to choose, learn more about installing packages.

Source Distributions

No source distribution files available for this release.See tutorial on generating distribution archives.

Built Distribution

url_for_s3-0.1.2-py2.py3-none-any.whl (3.7 kB view hashes)

Uploaded Python 2 Python 3

Supported by

AWS AWS Cloud computing and Security Sponsor Datadog Datadog Monitoring Fastly Fastly CDN Google Google Download Analytics Microsoft Microsoft PSF Sponsor Pingdom Pingdom Monitoring Sentry Sentry Error logging StatusPage StatusPage Status page